30p^2+22p-28=0

Solution for 30p^2+22p-28=0 equation:

30p^2+22p-28=0

a = 30; b = 22; c = -28;
Δ = b2-4ac
Δ = 222-4·30·(-28)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-62}{2*30}=\frac{-84}{60}
=-1+2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+62}{2*30}=\frac{40}{60}
=2/3
$